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A Canadian Wedding

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Old Jul 29, 2005 | 11:25 AM
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and let the jdm invasion continue


(the "other" jdm btw )
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Old Jul 29, 2005 | 11:32 AM
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(jdm x2) + (cdm x2) =


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Old Jul 29, 2005 | 11:36 AM
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bahhahahahahaha..
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Old Jul 29, 2005 | 11:48 AM
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Don't let it ever be said that I don't have math skills!
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Old Jul 29, 2005 | 11:57 AM
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Originally Posted by shareall,Jul 29 2005, 03:32 PM
(jdm x2) + (cdm x2) =


= 2(cdm) + (1/2(JDM) + 1/2(CDM))

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Old Jul 29, 2005 | 12:05 PM
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Originally Posted by Mocky57,Jul 29 2005, 03:57 PM
= 2(cdm) + (1/2(JDM) + 1/2(CDM))

Okay that's too complicated for me! I'm a social worker, not a freakin' mathematician! So much for appearing s-m-r-t.
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Old Jul 29, 2005 | 12:06 PM
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*hint* eric is born in canada




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Old Jul 29, 2005 | 12:06 PM
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From: Pt. A to Pt. B via VTEC!!
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Originally Posted by shareall,Jul 29 2005, 03:32 PM
(jdm x2) + (cdm x2) =


See orgy thread!
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Old Jul 29, 2005 | 12:10 PM
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Originally Posted by Mocky57,Jul 29 2005, 04:06 PM
*hint* eric is born in canada




Oh right I forgot!



but then isn't that equation missing one JDM then?

So it would be: 2(CDM) + (1/2(JDM) + 1/2(CDM)) + JDM
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Old Jul 29, 2005 | 12:11 PM
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Originally Posted by mikes2k,Jul 29 2005, 04:06 PM
See orgy thread!
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