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Old May 12, 2003 | 05:12 PM
  #41  
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no I was describing the situation being,

( Skuzzy / bitchslap ) * tokyo_james = ( tokyo_james + )^2
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Old May 12, 2003 | 05:15 PM
  #42  
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Ah I see, but if


( Skuzzy / bitchslap ) * tokyo_james = ( tokyo_james + )^2

isnt

( wicky/pimpslap ) * ( tokyo/skuzzy )^2 = owned

also true?

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Old May 12, 2003 | 05:23 PM
  #43  
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only if

(abs( tokyo_james * smackdown.func) = ~rumbled) +/- .01
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Old May 12, 2003 | 05:23 PM
  #44  
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[QUOTE]Originally posted by Skuzzy
[B]Ah I see, but if


( Skuzzy / bitchslap ) * tokyo_james = ( tokyo_james +
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Old May 12, 2003 | 05:24 PM
  #45  
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I assumed that [tokyo] was the truncated form of [tokyo_james] thereby maintaining the validity of the equation.
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Old May 12, 2003 | 05:25 PM
  #46  
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Oh yes, sorry about that mishap

( wicky/pimpslap ) * ( tokyo/skuzzy )^2 = owned'

tokyo=gay

Skuzzy=positively straight
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Old May 12, 2003 | 05:25 PM
  #47  
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Old May 12, 2003 | 05:29 PM
  #48  
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Originally posted by Skuzzy
Oh yes, sorry about that mishap

( wicky/pimpslap ) * ( tokyo/skuzzy )^2 = owned'

tokyo=gay

Skuzzy=positively straight
well if that's true then they cancel each other and you get

(tokyo/skuzzy = null) * ( wicky/pimpslap )^2 = (tokyo_james * smackdown.func)^4

(tokyo_james * smackdown.func)^4 = (tokyo_james^rumbled) +/- .01
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Old May 12, 2003 | 05:32 PM
  #49  
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((tokyo_james^rumbled) +/- .01) + skuzzy = [owned(tokyo_james)]^2
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Old May 12, 2003 | 05:35 PM
  #50  
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Whichever way you look at those ... it looks like I am ending up with a slap down and I honestly think that I thoroughly deserve it anyway .... so no arguments here !!!
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