New England's BIGGEST loser!
with all the weight loss talk going on.. it might be fun to have a New England's biggest loser contest..
of course Kev, Tommi, Ben and doug are excluded because something is genetically wrong with these skinny bastards
maybe a contest and at the end of six months or something the person who loses the most weight wins something
of course Kev, Tommi, Ben and doug are excluded because something is genetically wrong with these skinny bastards

maybe a contest and at the end of six months or something the person who loses the most weight wins something
[quote name='elmmx5' date='Mar 25 2007, 08:13 AM'] I don't think this would be fair since if I do end up actually getting the crack house I'm trying to, there will be no food budget.
I'm in if the winner is determined by a proportionate weight loss. In other words, we take the person's starting weight as the denominator and the same person's weight at the end of the contest as the numerator and then divide to get the percentage of weight the person now bears to his original weight. Example:
Person A weighs 200 pounds at the start and 175 pounds at the conclusion. 175/200 = .875 or 87.5% of the person's former weight. Using this method, the person with the lowest percentage wins.
Another option is to divide the total weight loss by the person's original weight. Example:
The person above lost 25 pounds so 25/200 = .125 or 12.5% of the person's original weight. Using this method, the person with the highest percentage wins.
Person A weighs 200 pounds at the start and 175 pounds at the conclusion. 175/200 = .875 or 87.5% of the person's former weight. Using this method, the person with the lowest percentage wins.
Another option is to divide the total weight loss by the person's original weight. Example:
The person above lost 25 pounds so 25/200 = .125 or 12.5% of the person's original weight. Using this method, the person with the highest percentage wins.









