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Can A Plane Take Off On A Treadmill?

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Old Jan 25, 2008 | 02:32 PM
  #21  
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Yes, the plane will lift off.
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Old Jan 25, 2008 | 02:47 PM
  #22  
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Originally Posted by S2020,Jan 25 2008, 03:17 PM
yes, but the airplane moves forward by pushing against air.
no, the ENGINE moves the plane forward. The thrust from the engine moves the plane forward. When the plane is moved forward, the air moving over the airfoil design of the wing creates a vaccum, causing lift. This is what keeps the airplane in the air. The lift of the wings counteract the force of gravity trying to pull the plane out of the sky. Thats why when engines fail, planes fall out of the sky, there isn't enough air moving over the wings to create enough lift.

This plane that is on the treadmill is going zero mph. There is no air going over the wings, creating no lift. Its the exact same thing as putting an r/c car on a treadmill, it is moving at zero mph.

The example of the runner on the treadmill is an excellent one, the is no fresh air hitting the runner's face. So, there wouldn't be any air moving over the plane's wings.

The point I'm trying to make is that in order for the plane to take off, there needs to be enough airflow pasing over the airfoil to lift the weight of the plane. And there is no airflow on the treadmill.
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Old Jan 25, 2008 | 02:49 PM
  #23  
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so an F1 car will stick to the ceiling when on a dyno?
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Old Jan 25, 2008 | 02:58 PM
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^lol. exactly.
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Old Jan 25, 2008 | 03:05 PM
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no, the ENGINE moves the plane forward. The thrust from the engine moves the plane forward. When the plane is moved forward, the air moving over the airfoil design of the wing creates a vaccum, causing lift. This is what keeps the airplane in the air. The lift of the wings counteract the force of gravity trying to pull the plane out of the sky. Thats why when engines fail, planes fall out of the sky, there isn't enough air moving over the wings to create enough lift.
Pretty much. Except the airfoils don't create vaccum. The lift is the result of the pressure difference over the "suction" side (the "top" side) and the "pressure" (the "bottom") side of an airfoil.

The air going over the "suction" side accelerates faster than the air over the "pressure" side of the airfoil. Faster air flow over the SS, in return, results in lower air pressure on SS than PS...the differential being the lift.
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Old Jan 25, 2008 | 03:06 PM
  #26  
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Originally Posted by antonio88x,Jan 25 2008, 07:47 PM
no, the ENGINE moves the plane forward. The thrust from the engine moves the plane forward. When the plane is moved forward, the air moving over the airfoil design of the wing creates a vaccum, causing lift. This is what keeps the airplane in the air. The lift of the wings counteract the force of gravity trying to pull the plane out of the sky. Thats why when engines fail, planes fall out of the sky, there isn't enough air moving over the wings to create enough lift.
no, the engine accelerates gas through combustion. The gas moves the plane forward
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Old Jan 25, 2008 | 06:10 PM
  #27  
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Originally Posted by Waitforme,Jan 25 2008, 06:49 PM
so an F1 car will stick to the ceiling when on a dyno?
Excellent analogy and the answer is no as well.
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Old Jan 25, 2008 | 06:33 PM
  #28  
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Originally Posted by antonio88x,Jan 25 2008, 06:47 PM
no, the ENGINE moves the plane forward. The thrust from the engine moves the plane forward. When the plane is moved forward, the air moving over the airfoil design of the wing creates a vaccum, causing lift. This is what keeps the airplane in the air. The lift of the wings counteract the force of gravity trying to pull the plane out of the sky. Thats why when engines fail, planes fall out of the sky, there isn't enough air moving over the wings to create enough lift.

This plane that is on the treadmill is going zero mph. There is no air going over the wings, creating no lift. Its the exact same thing as putting an r/c car on a treadmill, it is moving at zero mph.

The example of the runner on the treadmill is an excellent one, the is no fresh air hitting the runner's face. So, there wouldn't be any air moving over the plane's wings.

The point I'm trying to make is that in order for the plane to take off, there needs to be enough airflow pasing over the airfoil to lift the weight of the plane. And there is no airflow on the treadmill.
You're wrong about one thing. The plane on the treadmill is not going 0 miles an hour. Even if the treadmill is going 100 miles in a direction opposite of the direction the plane is travelling, the plane will move forward, it's just that the wheels will turn at the plane's speed + 100 mph.

The difference between a plane and a (runner,r/c car, etc) is that the wheels touching the treadmil are not what drives the airplane.

David
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Old Jan 25, 2008 | 07:01 PM
  #29  
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What your failing to understand is that the plane is NOT DRIVEN by the wheels! Therefore you cannot compare it to an RC car or a runner!

Heres the equation:

Max ground speed of plane -(minus) Speed at which plane needs to reach to achieve liftoff = MAX speed the treadmill can be moving in the opposite direction and the plane STILL TAKE OFF.

If the treadmill goes anything above that speed in the opposite direction, the plane will NOT take off because of the engines power capabilities not being able to overcome the belts opposite speed (Max ground speed is less than belt speed in opposite direction). In that case again, the plane will not take off.

I dont see whats so hard to understand here...
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Old Jan 25, 2008 | 08:45 PM
  #30  
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yeah i absolutely agree with most people. the plane will not take off on a treadmill. it would just be the wheels moving but essentially the plane is not moving. unless someone blows i giant fan to create enough airflow around the wing for lift...unlikely.

additionally, an F1 car creates no downforce on a dyno and can not stick to the ceiling. in a wind tunnel, yes! it is the airflow that creates lift and downforce.
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