can someone get back to me i need some help with some chemistry homework (i know you s2ki peeps are smart)

you are given the following equilibrium
NH4NO3(s) + H2O (l) --> NH4+ (aq) + NO3-

if we were told that the temp of the solution dropped from the initial measurements to the final measurements,what would these results indicate and where would go place the word "heat"in the above question?

any help is greatly appreciated

the + on NH4+ is a charge and the - on NO3- is also a charge

 

Heat would be one of the products on the right hand side of the equation. Since the solution is losing heat, that is one of the products of the initial solution as it changes to the newer state. I believe the loss of one oxygen atom has something to do with that as well.

I am not to sure about chemistry, it all seems like magic to me (and I have a hard Ike understanding any of it)

 

i agree on the magic part. thanks for the help ill take all and any i can get

 

Almost everything looks like magic until you start to understand it. Even to a magician.

 

the question is this- is it an exothermic reaction (did the reaction give off heat during the reaction thereby making the surrounding solution warmer) vs an endothermic reaction (did the reaction consume heat energy from that surrounding area during the reaction thereby becoming "colder")

if the temperature of the solution dropped, it means the above reaction took the surrounding heat energy to complete the process. as a result, you need to add heat to the equation on the EDIT- now that i've thought more about it, the heat is liberated on the right side, making the solution "colder".

at least, that would be my understanding.

darcy

 

I'm a magician and chemistry looks pretty straightforward to me.

"+ heat" goes on the right side of the equation. If the temperature drops going from the left to the right, then it has to rise going right to left; i.e., you have to add heat.

 

Where to see the loss of an oxygen atom? All I see is that dissolving ammonium nitrate in water gives you a(n aqueous) solution of ammonium ions and nitrate ions.