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Old Jun 14, 2006 | 01:46 PM
  #61  
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The patent office no longer takes applications for perpetual motion machines unless you have a working device that has ran for atleast one year without stopping (and runs under it's own power of course )
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Old Jun 14, 2006 | 02:04 PM
  #62  
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Originally Posted by NFRs2000NYC,Jun 14 2006, 04:40 PM
Yup.

Although (and I am not arguing at all)....are you sure I am is not a sentence?

If I say.... "Are you full?" and you say "I am" is that not a sentence?

Also, same example, but if you say "I am, thank you." That is a sentence. It also doesnt have a followup noun.

Just wondering....
.. "I am full"
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Old Jun 14, 2006 | 04:38 PM
  #63  
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Did you know, everybody on this site knows what a s2000 is.
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Old Jun 14, 2006 | 04:55 PM
  #64  
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Did you know that JYD (Junk Yard Dog) from the WWF & NWA died in 1988 in a car accident at age 45?

Did you know the S2000 cruise control works in reverse as long as you are going 25mph or faster?

Did you know that the S2000 does 48 miles per hour in reverse?

Did you know that a full size tires fits into the trunk of the S2000 and the trunk will close.

Did you know Miss Elizabeth (Elizabeth Hulette) died in 2003 at age 42

Did you know that I HATE PEOPLE WHO WASTE MONEY ON BLING TONES, PUFFY JACKETS, AND GRILLS?

Did you know that Ravishing Rick Rude died in 1999 at age 40

Did you know that the real red ranger from the Power Rangers is actually "Turbo_Pwr" on this board?

Did you know if you forget to put your hood pins in on a racing S2000 that the ****ing hood will blow up and bend to all shit but sometimes not break your windshield.
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Old Jun 14, 2006 | 05:02 PM
  #65  
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If you have a 1" diameter shaft and want a string to encircle the shaft the string would be ~3.14" long. If you wanted the string to have 6" of clearance all the way around the shaft you would add ~37.7" to the original length.

If you had a string encircle the entire earth how much string would you have to add to allow 6" of clearance all the way around the earth?





















~37.7 " Whoa!!!!!

Circumference of a circle = PI x Dia.

If you increase the dia. by 1 foot

Circum. of circle = PI x (Dia. + 1)

PI x 1" = 3.14 feet = 37.7"
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Old Jun 14, 2006 | 05:48 PM
  #66  
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Originally Posted by Scot,Jun 14 2006, 04:55 PM
Did you know that the real red ranger from the Power Rangers is actually "Turbo_Pwr" on this board?
Seriously?
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Old Jun 14, 2006 | 06:08 PM
  #67  
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Originally Posted by Scot,Jun 14 2006, 07:55 PM
Did you know that the real red ranger from the Power Rangers is actually "Turbo_Pwr" on this board?
I'd rather know the pink power ranger. Amy Jo is HOT!
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Old Jun 14, 2006 | 07:20 PM
  #68  
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Originally Posted by VoIPA,Jun 14 2006, 09:08 PM
I'd rather know the pink power ranger. Amy Jo is HOT!
pink = scratch and sniff....
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Old Jun 14, 2006 | 11:04 PM
  #69  
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Originally Posted by Greenlight,Jun 15 2006, 11:02 AM
If you have a 1" diameter shaft and want a string to encircle the shaft the string would be ~3.14" long. If you wanted the string to have 6" of clearance all the way around the shaft you would add ~37.7" to the original length.

If you had a string encircle the entire earth how much string would you have to add to allow 6" of clearance all the way around the earth?





















~37.7 " Whoa!!!!!

Circumference of a circle = PI x Dia.

If you increase the dia. by 1 foot

Circum. of circle = PI x (Dia. + 1)

PI x 1" = 3.14 feet = 37.7"
Did you know that this omits the important lines of working and contains so many errors its hard to even test if what you "meant" to say is correct?



" = inches

' = feet


Next when you're trying to illustrate the difference using equations you should show the line Circumference(using Dearth + 1') - Circumference(using Dearth) =

So it would be

PiD2 - PiD1 =x (where D2=D1+1') substitution gives
Pi(D1+1')-PiD1
Pi.D1 + Pi.1' - PiD1=x Therefore....
x=Pi' where x is the difference in circumference.

[/procrastination]
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Old Jun 14, 2006 | 11:09 PM
  #70  
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Originally Posted by gosixers215,Jun 12 2006, 03:44 PM
You're not. You eat at least 16.
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