An equation my friend gave me to solve but I'm a little lost. I can do the determinent and I believe the summation equal (infinity) but what do i do with the beta? I assume they eventually cancel out but don't know how to go about it. And I haven't done any integration since university either and that was a while ago =(

 

Don't do it...

 

 

Beta never really caught on, while the quality wasn't as good everyone migrated to VHS because of cheaper cost and longer recording time. VHS was phased out due to the DVD and DVR.

 

The answer is always pi. Or pie. I like pie.

 

Well the integral is 625 and the determinant is 37, so 416-(625-37)=-172...but that doesn't include the summation and beta part

I didn't really go past calc 1 though, so I'm unfamiliar with beta and what I assume is alpha there. Can I treat them as regular variables?

 

I believe Deep Thought said the answer was "42"

 

-173

 

Technically, it's not an equation as there's no equal sign; it's a formula.

The summation is finite - all alternating series where the terms approach zero converge - though it isn't one with which I'm immediately familiar. Beta is just a variable here, and I believe that the terms involving beta will not cancel. Hence, the solution - well, simplification, actually - will contain beta, still as a variable.

Is this simply something your friend - your term, not mine - gave you to vex you? It's hard to imagine how this bizarre combination of symbols would arise in any problem of practical value. Also, his use of "det" is suspicious: the notation |A| (where A is a square matrix) means the determinant of the matrix, so "det" is superfluous. I suspect that this is an arbitrary collection of symbols aggregated by someone who doesn't understand their meaning.

 

The infinite sum is equal to e[sup](-1/2)[/sup].
Yes beta ultimately cancels out.
Gaja