problem solvers answer this
What is the probability of tossing a coin three times and the outcome being one head and two tails (in any order)?
a) 1/2
b) 1/4
c) 3/8
d) 5/8
e) 3/4
I came up with a different answer then the what was given as the correct one. I want to see what you guys come up with.
below is my logic:
To me the answer is 1/4. Reasoning: Only 4 outcomes - 3 heads, 3 tails, 2 heads and 1 tail, or 2 tails and 1 head.
Btw, this is the answer given:
Probability of throwing head (H) = 1/2
Probability of throwing tail (T) = 1/2
P(TTH) = 1/2 x1/2 x1/2 = 1/8
P(THT) = 1/2 x1/2 x1/2 = 1/8
P(HTT) = 1/2 x1/2 x1/2 = 1/8
=3/8
discuss...
a) 1/2
b) 1/4
c) 3/8
d) 5/8
e) 3/4
I came up with a different answer then the what was given as the correct one. I want to see what you guys come up with.
below is my logic:
To me the answer is 1/4. Reasoning: Only 4 outcomes - 3 heads, 3 tails, 2 heads and 1 tail, or 2 tails and 1 head.
Btw, this is the answer given:
Probability of throwing head (H) = 1/2
Probability of throwing tail (T) = 1/2
P(TTH) = 1/2 x1/2 x1/2 = 1/8
P(THT) = 1/2 x1/2 x1/2 = 1/8
P(HTT) = 1/2 x1/2 x1/2 = 1/8
=3/8
discuss...
If it's a fair coin (which isn't stipulated, by the way), then the answer is 3/8.
There are eight possible outcomes, all equally likely:
HHH
HHT
HTH
THT
HTT
THT
TTH
TTT
Three of them have one head and two tails.
There are eight possible outcomes, all equally likely:
HHH
HHT
HTH
THT
HTT
THT
TTH
TTT
Three of them have one head and two tails.
3 heads
HHH
3 tails
TTT
2 heads and 1 tail
HHT
HTH
THH
2 tails and 1 head
TTH
THT
HTT
So, HHH + TTT + 3 versions of (2H & 1T) + 3 versions of (1H & 2T) = 8
How many times did 1H & 2T come up? 3 times, so 3/8.
Trending Topics
Originally Posted by vtec9,Jul 21 2008, 10:30 AM
100% of statistics are right 75% of the time.








tail and head.