So what angles are used to build the box in the middle on this link?

http://www.geocities.com/mariobonifa...asurements.htm

 

http://www.ddgps.com/textweb/UNIT%203%20Ge...%20GEOMETRY.htm

 

You kill me sometimes William.....

:campbuds:


What angle are you having a problem with? Is it these pieces? \ / ?

 

Thanks for the geometry lesson!!

Yes I am referring to the \ /

What angles do i need the sides at to make it all line up all pretty.

Unfotunately in my accounting I have yet to use geometry.

 

Wait what about this!

http://www.1728.com/quadtrap.htm

The only thing I see then is taking into account the thickness of the wood (3/4") when figuring the length of the sides.

So I still need some help here...

 

Her you go:

http://www.webmath.com/rtri.html

With values entered.

http://www.webmath.com/cgi-bin/rtri.cgi?c=...e=&b=&d=%3F&a=3

You know the hypotenuse is 7.125 and side A is equal to (23 - 17)/2 (or 3")

This gives you an approximate angle of 65 degrees

 

Has no one ever built this box before?

 

the 7.125 sides.... wouldn't they become 8.625 with the 3/4 thickness of the wood?

 

didn't i figure this one out a couple years ago?

regretfully, i never key worded it. i think i figured it out for ajira...


sure enough, i did.

http://forums.s2ki.com/forums/index.php?showtopic=185903

read up on that thread, it should help ya out. (i'm pretty sure it's the same enclosure... yup it is.)

 

ok while that helped a bit, I am still struggling with the depth of the box. What is the actual hieght of the trapezoid on the sides of the box?

(not the length of it's sides but it's actual height?)