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4.57's question

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Old Sep 11, 2006 | 05:58 PM
  #11  
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See further down, this is wrong
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Old Sep 11, 2006 | 06:00 PM
  #12  
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Originally Posted by Spec_Ops2087,Sep 11 2006, 06:58 PM
when the engine spins one full rotation the diff spins the wheels 4.10 times (stock) but with the gears it will spin 4.57 times per one engine rotation approx.
No. This is so wrong it is scary.
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Old Sep 11, 2006 | 06:46 PM
  #13  
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You have your numbers backwards Spec Ops, for you would be going for top speed. Also, there are ratios for each gear you didn't take into account. Now if you said for each time the driveshaft spins 4.57 times the wheels spin 1 time, then you would be correct. Imagine a picture of the ring and pinion, the ring has lots of teeth, the pinion has few.

Anywho, no harm done.

By all means some one correct me if I'm wrong.
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Old Sep 11, 2006 | 06:49 PM
  #14  
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Whops that was a typo I'll fix it
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Old Sep 11, 2006 | 06:49 PM
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No worries.
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Old Sep 11, 2006 | 06:56 PM
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Originally Posted by TheCarGuy2021,Sep 11 2006, 07:46 PM
Now if you said for each time the driveshaft spins 4.57 times the wheels spin 1 time, then you would be correct.
It's not necessarily 1:1 for the ring and the wheels, either. That's the whole point of the differential, in fact. It allows the wheels to turn at different speeds, so obviously they can't both be turning at the same speed as the ring gear. If the car is going straight it *might* be 1:1, but I doubt it.

There are 4.57 ring teeth for every pinon tooth. That's the actual definition involved here.

His original "typo" was wrong about the driveshaft being 1:1 to the engine, wrong about the ring being 1:1 to the wheels, wrong about which way the gear reduction works (he had it inverted), and wrong about the relationship between torque and speed (he also had that inverted).

Originally Posted by Spec_Ops2087,Sep 11 2006, 06:58 PM
In other words, you gain no power but your wheels spin faster then what they would with the stock gears.
Even his "correction" still claims that the the 4.57 gear turns the wheels faster than the 4.10 gear. He clearly doesn't have a clue.

Like I said, so wrong it was scary.
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Old Sep 11, 2006 | 07:04 PM
  #17  
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Thank you for clearing that up sir.
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Old Sep 11, 2006 | 07:46 PM
  #18  
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thank you everyone
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Old Sep 11, 2006 | 08:32 PM
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layman's
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Old Sep 11, 2006 | 08:42 PM
  #20  
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Originally Posted by mikegarrison,Sep 11 2006, 09:56 PM
It's not necessarily 1:1 for the ring and the wheels, either. That's the whole point of the differential, in fact. It allows the wheels to turn at different speeds, so obviously they can't both be turning at the same speed as the ring gear. If the car is going straight it *might* be 1:1, but I doubt it.

There are 4.57 ring teeth for every pinon tooth. That's the actual definition involved here.

His original "typo" was wrong about the driveshaft being 1:1 to the engine, wrong about the ring being 1:1 to the wheels, wrong about which way the gear reduction works (he had it inverted), and wrong about the relationship between torque and speed (he also had that inverted).


Even his "correction" still claims that the the 4.57 gear turns the wheels faster than the 4.10 gear. He clearly doesn't have a clue.

Like I said, so wrong it was scary.
I could have sworn that was what Xviper said as the approx definition of the gears. I guess I misread it.

No the driveshaft is not 1:1 with the engine...there are transmission gears (as I said, I mean't to write it the other way)

the ring is approx 1:1 if the car is going straight....we don't need to be EXACT here nor do we need to account for the LSD.

The car gains "torque" (even though it really doesn't) because the engine is doing the same work for "less." Its like using a small pulley instead of a large pulley. Mechanical Advantage at work.


No need to give a somewhat rude response.
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