17" or 18" which one?
The weight difference isn't tremendous either way, but if you peruse 17" and 18" wheel weights in the same model and width, the 18" is always heavier. Then look at same-model/same-width/same-height tire weights, usually the 17" tire is a little heavier, but not always.
The 18" combo will almost always be heavier overall.
Ferinstance:
OZ Allegerita 17x8.5 = 15.6 lb., 18x8.5 = 17.4 lb., 1.8 lb. heavier
Bridgestone RE11 255/40-17 = 26 lb., 255/35-18 = 27 lb., 1 lb. heavier
As for tire weight being "farest"(?) from center, the tread of a 255/40-17 vs. a 255/35-18 is the same distance from center. Any additional tire mass is in the sidewall right at the rim. I would bet that the polar moments of 18" vs. 17" wheel+tire are going to be very close.
In the end, the weight difference and polar moment difference isn't going to be enough to make for a measurable performance difference anyway.
So the question is: Why spend WAY more on 18" wheels/tires for zero performance benefit?
The 18" combo will almost always be heavier overall.
Ferinstance:
OZ Allegerita 17x8.5 = 15.6 lb., 18x8.5 = 17.4 lb., 1.8 lb. heavier
Bridgestone RE11 255/40-17 = 26 lb., 255/35-18 = 27 lb., 1 lb. heavier
As for tire weight being "farest"(?) from center, the tread of a 255/40-17 vs. a 255/35-18 is the same distance from center. Any additional tire mass is in the sidewall right at the rim. I would bet that the polar moments of 18" vs. 17" wheel+tire are going to be very close.
In the end, the weight difference and polar moment difference isn't going to be enough to make for a measurable performance difference anyway.
So the question is: Why spend WAY more on 18" wheels/tires for zero performance benefit?
Originally Posted by ZDan,Jul 21 2009, 02:12 PM
The weight difference isn't tremendous either way, but if you peruse 17" and 18" wheel weights in the same model and width, the 18" is always heavier. Then look at same-model/same-width/same-height tire weights, usually the 17" tire is a little heavier, but not always.
The 18" combo will almost always be heavier overall.
Ferinstance:
OZ Allegerita 17x8.5 = 15.6 lb., 18x8.5 = 17.4 lb., 1.8 lb. heavier
Bridgestone RE11 255/40-17 = 26 lb., 255/35-18 = 27 lb., 1 lb. heavier
As for tire weight being "farest"(?) from center, the tread of a 255/40-17 vs. a 255/35-18 is the same distance from center. Any additional tire mass is in the sidewall right at the rim. I would bet that the polar moments of 18" vs. 17" wheel+tire are going to be very close.
In the end, the weight difference and polar moment difference isn't going to be enough to make for a measurable performance difference anyway.
So the question is: Why spend WAY more on 18" wheels/tires for zero performance benefit?
The 18" combo will almost always be heavier overall.
Ferinstance:
OZ Allegerita 17x8.5 = 15.6 lb., 18x8.5 = 17.4 lb., 1.8 lb. heavier
Bridgestone RE11 255/40-17 = 26 lb., 255/35-18 = 27 lb., 1 lb. heavier
As for tire weight being "farest"(?) from center, the tread of a 255/40-17 vs. a 255/35-18 is the same distance from center. Any additional tire mass is in the sidewall right at the rim. I would bet that the polar moments of 18" vs. 17" wheel+tire are going to be very close.
In the end, the weight difference and polar moment difference isn't going to be enough to make for a measurable performance difference anyway.
So the question is: Why spend WAY more on 18" wheels/tires for zero performance benefit?
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vietdragontekx
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