Member name Posts
Lovetodrive2000 664
FluKy15 384
s2kmiami69 342
LINESUPER 79
Scooterboy 58
kgf3076 56
RedCelica 11

 

 

I think almost all cars will take the same amount of time in the 1/4 mile....

If the 1/4 mile is vertical and they are dropped from a plane!

 

 

That being said.....

Bet they all would stop in the same distance if they were dropped from an airplane!

 

Not necessarily...you must calculate for mass, drag and surface area as well.



where
Vt = terminal velocity,
m = mass of the falling object,
g = acceleration due to gravity,
Cd = drag coefficient,
ρ = density of the fluid through which the object is falling, and
A = projected area of the object.

So an s2000 might have a terminal velocity of:

m = 2850 lbs
g = 32.174 fps^2
Cd = 0.29 (top up)
p = http://en.wikipedia.org/wiki/Density_of_air assumed 25 deg C (77F) air temp avg. density is calculated as 1.1839 kg/m^-3 or .7513148 kg/m converted to lb/ft = 5.43439476286025 lb/ft
A = This is kinda hard, so Im going to guess knowing that the s2000 is 68.9 in wide and 50.0 in high and then take 33% of that is roughly 94.7375 ft^2

sqroot of 183391.8/149.304 = 35.047 fps

The terminal velocity of an S2000 is approx. 35.047 feet per second.

Using the basic formula for a falling object sqroot(2d/v) = sqroot(2640/35.0470) = 8.679 seconds @ 207.27 mph

The result assumes that the 1320 ft begins with the point at which the vehicle reaches terminal velocity...I'll have to calculate the differentiation between acceleration between initial and terminal velocities.

Now...please someone check my math

 

not even close.

 

His fast what?

 

 

Math is wrong..... but you have to find out where!