1 = 2 ??????
A colleague gave me an interesting 1=2. Not too hard to figure out the flaw, but interesting:
1^2 = 1
2^2 = 2 + 2
3^2 = 2 + 2 + 3
4^2 = 4 + 4 + 4 + 4
and so forth... algebraically this is:
x^2 = {x + x + x ...} for x terms
differentiate
2x = {1 + 1 + 1 ...} for x terms, which = x
Thus
2x = 1x
2 = 1
1^2 = 1
2^2 = 2 + 2
3^2 = 2 + 2 + 3
4^2 = 4 + 4 + 4 + 4
and so forth... algebraically this is:
x^2 = {x + x + x ...} for x terms
differentiate
2x = {1 + 1 + 1 ...} for x terms, which = x
Thus
2x = 1x
2 = 1
One can make it more obscure by using more sophisticated mathematics:
2 = e^(ln 2) = [e^(ln 2)]^[(i*2*pi)/(i*2*pi)] = [e^(i*2*pi)]^[(ln 2)/(i*2*pi)] = 1^[(ln 2)/(i*2*pi)] = 1.
This uses the fact that e^bi = cos(b) + i*sin(b), and 1^x = 1.
2 = e^(ln 2) = [e^(ln 2)]^[(i*2*pi)/(i*2*pi)] = [e^(i*2*pi)]^[(ln 2)/(i*2*pi)] = 1^[(ln 2)/(i*2*pi)] = 1.
This uses the fact that e^bi = cos(b) + i*sin(b), and 1^x = 1.
I was wondering when you would jump into this one 

Originally posted by magician
One can make it more obscure by using more sophisticated mathematics:
2 = e^(ln 2) = [e^(ln 2)]^[(i*2*pi)/(i*2*pi)] = [e^(i*2*pi)]^[(ln 2)/(i*2*pi)] = 1^[(ln 2)/(i*2*pi)] = 1.
This uses the fact that e^bi = cos(b) + i*sin(b), and 1^x = 1.
One can make it more obscure by using more sophisticated mathematics:
2 = e^(ln 2) = [e^(ln 2)]^[(i*2*pi)/(i*2*pi)] = [e^(i*2*pi)]^[(ln 2)/(i*2*pi)] = 1^[(ln 2)/(i*2*pi)] = 1.
This uses the fact that e^bi = cos(b) + i*sin(b), and 1^x = 1.
being in algebra 2 (oh yea : P) i see division all the time...but yea.....i thought he was listing a system....not a step by step problem..as i had no idea why one would spontaneoulsy decide to square numbers without reason..but i guess there was a reason and that was to make an incorrect problem so yea....
Originally posted by LordVagabond
I can't do calculus... hell, I can barely understand infinite theory calculations... but physics, for some odd reason, I am a natural at
I can't do calculus... hell, I can barely understand infinite theory calculations... but physics, for some odd reason, I am a natural at






