Any calculus brains out there?
find f(a+h) - f(a) for the following function: f(x) = x^2 - 2x + 1
can anyone give me a step by step guide to do this? yeah yeah, I know its easy and I should know it. feel free to poke fun
thanks in advance
can anyone give me a step by step guide to do this? yeah yeah, I know its easy and I should know it. feel free to poke fun
thanks in advance
Sigh.
This is not a calculus question; it's an algebra question.
f(x) = x^2 - 2x + 1, so
f(a) = a^2 - 2a + 1, and
f(a + h) = (a + h)^2 - 2(a + h) + 1.
f(a + h) - f(a) = (a + h)^2 - 2(a + h) + 1 - [a^2 -2a + 1].
The rest is up to you.
This is not a calculus question; it's an algebra question.
f(x) = x^2 - 2x + 1, so
f(a) = a^2 - 2a + 1, and
f(a + h) = (a + h)^2 - 2(a + h) + 1.
f(a + h) - f(a) = (a + h)^2 - 2(a + h) + 1 - [a^2 -2a + 1].
The rest is up to you.
lol wheres the calculus in that? i was expecting the definition of derivative with limit h>0 and the whole equation /h, but nope didnt even get THAT, and thats not even calculus thats pre-cal =(.
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