any PHYSICS GURU here? - I have vector problem...
Thread Starter
Registered User
Joined: Dec 2001
Posts: 11
Likes: 0
From: Santa Fe
any PHYSICS GURU here? - I have vector problem...
any PHYSICS GURU here? - I have vector problem...
Given:
V1 8.08 units at negative x axis
v2 4.51 units at 45 degree positve axis
I know the formula is:
Vy = Vcos(degree) = 4.51(cos45) = 3.12
Vx = Vcos(degree) = 8.08 (sin?) = ??
How am i suppose to find components of Vy without degree given?
Help me
Given:
V1 8.08 units at negative x axis
v2 4.51 units at 45 degree positve axis
I know the formula is:
Vy = Vcos(degree) = 4.51(cos45) = 3.12
Vx = Vcos(degree) = 8.08 (sin?) = ??
How am i suppose to find components of Vy without degree given?
Help me
Registered User
Joined: Jul 2001
Posts: 6,592
Likes: 0
From: Yorba Linda, CA
Whilst I'm not a physics guru, I do have a couple of degrees in math. You have "V1 8.08 units at negative x axis"; it seems to me that the angle would be 180 degrees measured counterclockwise from the positive x-axis.
Former Moderator
Joined: Jan 2001
Posts: 2,751
Likes: 1
From: Arlington, VA
It's not entirely clear to me what exactly you're looking for, but on the assumption you want the x and y components of each vector:
Vx1 = V1cos(theta) = 8.08cos(180) = 8.08
Vy1 = V1sin(theta) = 8.08sin(180) = 0
Vx2 = V2 cos(theta) = 4.51cos(45)
Vy2 = V2 sin(theta) = 4.51sin(45)
Vx1 = V1cos(theta) = 8.08cos(180) = 8.08
Vy1 = V1sin(theta) = 8.08sin(180) = 0
Vx2 = V2 cos(theta) = 4.51cos(45)
Vy2 = V2 sin(theta) = 4.51sin(45)
Thread
Thread Starter
Forum
Replies
Last Post