math help v. discrete math... test tomorrow!
3a. 9C6 X 7 + 9C7 = 708
Case 1. 6 women on committee
9 women choose 6 multiply with any men.
Case 2 All women on committee
9 female choose 7
Add case 1 and case 2 to obtain total
3b. 15C6 X 2 = 10010
15 choose 6 multiply by 2 since it has to be bob or alice. Or 15C6 with alice plus 15 choose 6 with bob.
I hope i got that right.
Case 1. 6 women on committee
9 women choose 6 multiply with any men.
Case 2 All women on committee
9 female choose 7
Add case 1 and case 2 to obtain total
3b. 15C6 X 2 = 10010
15 choose 6 multiply by 2 since it has to be bob or alice. Or 15C6 with alice plus 15 choose 6 with bob.
I hope i got that right.
Originally Posted by S2020' date='Mar 26 2007, 11:06 AM
yeah but if need be I can pretty much relearn all of them in a hurry....
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