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math question... have a test tomorrow.. help!

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Old Mar 25, 2007 | 08:22 PM
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Default math question... have a test tomorrow.. help!

this is the last one.. please help. thanks!


4. Twelve ships enter the St. Jhon
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Old Mar 25, 2007 | 08:42 PM
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ttt
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Old Mar 25, 2007 | 08:46 PM
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Off hand, I'd say that if your test's tomorrow it's a little late to be getting help on these.

Whatever.

a. 12!
b. 9! * 3! * 2!
c. 8! * 5!
d. 12! - (11! * 2!)
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Old Mar 25, 2007 | 09:02 PM
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Originally Posted by magician' date='Mar 25 2007, 08:46 PM
Off hand, I'd say that if your test's tomorrow it's a little late to be getting help on these.

Whatever.

a. 12!
b. 9! * 3! * 2!
c. 8! * 5!
d. 12! - (11! * 2!)
thanks so much! how did you get the solutions to b,c, and d? im going to have similar problems on my test tomorrow and it would be really helpful if you can just show me how you worked it out...

thanks again.
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Old Mar 25, 2007 | 09:17 PM
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b. There are nine "groups" of ships: the Canadian ships form one group (1), each of the Portuguese ships is a group (2, 3, 4), the Icelandic ships form one group (5), the Greenlandic (?) ships each form a group (6, 7), the Bahamian ship is a group (8), and the American ship is a group (9): there are 9! ways to arrange the groups. For each such arrangement, there are 3! ways the Canadian ships can enter, and 2! ways the Icelandic ships can enter. Hence, 9! * 3! * 2!.

c. There are eight groups: 3 Portguese, 2 Greenlandic, 1 Bahamian, 1 American, and 1 Icelandic-Canadian (Iceladian? Canadandic?), so there are 8! ways the groups can come in; for each such arrangement, there are 5! ways the Iceladian / Canadandic ships can come in. Hence, 8! * 5!.

d. There are 12! ways for the ships to come in. If the American and Bahamian (Amerihamian?) ships are together, there are 11 groups and 11! * 2! ways to come in. If they're not together, that must be the remaining 12! - (11! * 2!) ways.
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Old Mar 25, 2007 | 09:23 PM
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Just Magician doing what he does best. Danger, you're lucky you're getting help from a college math professor but you really should've learned this stuff beforehand.
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Old Mar 25, 2007 | 09:26 PM
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thank you so much! this definately helped!
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Old Mar 25, 2007 | 09:26 PM
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Originally Posted by magician' date='Mar 25 2007, 09:17 PM
b. There are nine "groups" of ships: the Canadian ships form one group (1), each of the Portuguese ships is a group (2, 3, 4), the Icelandic ships form one group (5), the Greenlandic (?) ships each form a group (6, 7), the Bahamian ship is a group (8), and the American ship is a group (9): there are 9! ways to arrange the groups. For each such arrangement, there are 3! ways the Canadian ships can enter, and 2! ways the Icelandic ships can enter. Hence, 9! * 3! * 2!.

c. There are eight groups: 3 Portguese, 2 Greenlandic, 1 Bahamian, 1 American, and 1 Icelandic-Canadian (Iceladian? Canadandic?), so there are 8! ways the groups can come in; for each such arrangement, there are 5! ways the Iceladian / Canadandic ships can come in. Hence, 8! * 5!.

d. There are 12! ways for the ships to come in. If the American and Bahamian (Amerihamian?) ships are together, there are 11 groups and 11! * 2! ways to come in. If they're not together, that must be the remaining 12! - (11! * 2!) ways.
Damn
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Old Mar 25, 2007 | 09:28 PM
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Originally Posted by Daniel L' date='Mar 25 2007, 09:23 PM
Just Magician doing what he does best. Danger, you're lucky you're getting help from a college math professor but you really should've learned this stuff beforehand.
you're absolutely right.. thats why im stayin up tonight and payin for it.. its 130est and i dont plan on goin to bed anytime soon.


thanks again magician
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Old Mar 25, 2007 | 09:49 PM
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Originally Posted by Daniel L' date='Mar 25 2007, 09:23 PM
Just Magician doing what he does best.
You flatter me.

Originally Posted by Daniel L' date='Mar 25 2007, 09:23 PM
Danger, you're lucky you're getting help from a college math professor but you really should've learned this stuff beforehand.
As I believe I mentioned in my initial response. Thanks for backing me up on this.
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