math question... have a test tomorrow.. help!
Originally Posted by magician' date='Mar 25 2007, 08:46 PM
Off hand, I'd say that if your test's tomorrow it's a little late to be getting help on these.
Whatever.
a. 12!
b. 9! * 3! * 2!
c. 8! * 5!
d. 12! - (11! * 2!)
Whatever.
a. 12!
b. 9! * 3! * 2!
c. 8! * 5!
d. 12! - (11! * 2!)
thanks again.
b. There are nine "groups" of ships: the Canadian ships form one group (1), each of the Portuguese ships is a group (2, 3, 4), the Icelandic ships form one group (5), the Greenlandic (?) ships each form a group (6, 7), the Bahamian ship is a group (8), and the American ship is a group (9): there are 9! ways to arrange the groups. For each such arrangement, there are 3! ways the Canadian ships can enter, and 2! ways the Icelandic ships can enter. Hence, 9! * 3! * 2!.
c. There are eight groups: 3 Portguese, 2 Greenlandic, 1 Bahamian, 1 American, and 1 Icelandic-Canadian (Iceladian? Canadandic?), so there are 8! ways the groups can come in; for each such arrangement, there are 5! ways the Iceladian / Canadandic ships can come in. Hence, 8! * 5!.
d. There are 12! ways for the ships to come in. If the American and Bahamian (Amerihamian?) ships are together, there are 11 groups and 11! * 2! ways to come in. If they're not together, that must be the remaining 12! - (11! * 2!) ways.
c. There are eight groups: 3 Portguese, 2 Greenlandic, 1 Bahamian, 1 American, and 1 Icelandic-Canadian (Iceladian? Canadandic?), so there are 8! ways the groups can come in; for each such arrangement, there are 5! ways the Iceladian / Canadandic ships can come in. Hence, 8! * 5!.
d. There are 12! ways for the ships to come in. If the American and Bahamian (Amerihamian?) ships are together, there are 11 groups and 11! * 2! ways to come in. If they're not together, that must be the remaining 12! - (11! * 2!) ways.
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Originally Posted by magician' date='Mar 25 2007, 09:17 PM
b. There are nine "groups" of ships: the Canadian ships form one group (1), each of the Portuguese ships is a group (2, 3, 4), the Icelandic ships form one group (5), the Greenlandic (?) ships each form a group (6, 7), the Bahamian ship is a group (8), and the American ship is a group (9): there are 9! ways to arrange the groups. For each such arrangement, there are 3! ways the Canadian ships can enter, and 2! ways the Icelandic ships can enter. Hence, 9! * 3! * 2!.
c. There are eight groups: 3 Portguese, 2 Greenlandic, 1 Bahamian, 1 American, and 1 Icelandic-Canadian (Iceladian? Canadandic?), so there are 8! ways the groups can come in; for each such arrangement, there are 5! ways the Iceladian / Canadandic ships can come in. Hence, 8! * 5!.
d. There are 12! ways for the ships to come in. If the American and Bahamian (Amerihamian?) ships are together, there are 11 groups and 11! * 2! ways to come in. If they're not together, that must be the remaining 12! - (11! * 2!) ways.
c. There are eight groups: 3 Portguese, 2 Greenlandic, 1 Bahamian, 1 American, and 1 Icelandic-Canadian (Iceladian? Canadandic?), so there are 8! ways the groups can come in; for each such arrangement, there are 5! ways the Iceladian / Canadandic ships can come in. Hence, 8! * 5!.
d. There are 12! ways for the ships to come in. If the American and Bahamian (Amerihamian?) ships are together, there are 11 groups and 11! * 2! ways to come in. If they're not together, that must be the remaining 12! - (11! * 2!) ways.
Originally Posted by Daniel L' date='Mar 25 2007, 09:23 PM
Just Magician doing what he does best. Danger, you're lucky you're getting help from a college math professor but you really should've learned this stuff beforehand.
thanks again magician
Originally Posted by Daniel L' date='Mar 25 2007, 09:23 PM
Just Magician doing what he does best.
Originally Posted by Daniel L' date='Mar 25 2007, 09:23 PM
Danger, you're lucky you're getting help from a college math professor but you really should've learned this stuff beforehand.



