headlight output..
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[QUOTE]Originally posted by MacGyver
[B]I don't think any of us has been able to write a sentence the others can fully understand
I THINK what dun was TRYING to say was moving more of the shield out of the way (believing the shield comes from the top of the light down, hence increasing the height to move it out of the way more) and then aiming the light down at a greater angle to compensate for the higher cutoff point.
[B]I don't think any of us has been able to write a sentence the others can fully understand
I THINK what dun was TRYING to say was moving more of the shield out of the way (believing the shield comes from the top of the light down, hence increasing the height to move it out of the way more) and then aiming the light down at a greater angle to compensate for the higher cutoff point.
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Originally posted by dundonr
exactly.. and this SHOULD allow more light on the road, without blinding anyone...
exactly.. and this SHOULD allow more light on the road, without blinding anyone...
Basically, what I gather from your statements is that you believe the cutoff is an overhanging shielding that "cuts off" the top half of the beam. If you crack open that old Physics book again, you'll remember that planoconvex lenses invert the image projected onto the planar surface and project that inverted image out the convex surface. The shielding is actually on the lower half of the ellipsoid. The upper half of the entire beam is allowed to pass onto the planar surface and then is inverted and projected out the lower half of the convex surface.
The reason your idea doesn't work is because the shape of the ellipsoid doesn't focus more light towards the very upper half of the beam before it is inverted. If you raise the cutoff shield, you'll not only get a lower cutoff, you'll get less actual light. There is a better solution to the problem of glare and flashing, but I haven't figured out a proper way to implement it yet.
Hope that clarifies things,
Rich
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