Car and Bike Talk Discussions and comparisons of cars and motorcycles of all makes and models.
View Poll Results: HP -> Acceleration... not Torque!
HP is more important than Torque
58.62%
Torque is more important than HP
41.38%
Voters: 203. You may not vote on this poll

HP -> Acceleration... not Torque!

Thread Tools
 
Old Jun 10, 2003 | 11:23 AM
  #181  
Zoran's Avatar
Registered User
 
Joined: Apr 2001
Posts: 854
Likes: 0
From: Houston
Default

[QUOTE]Originally posted by wc_one
[B]Zoran, you seem to be confusing acceleration and speed, the two are very different.
Reply
Old Jun 10, 2003 | 02:21 PM
  #182  
wc_one's Avatar
Registered User
 
Joined: Jan 2002
Posts: 250
Likes: 0
From: Redford, MI
Default

[QUOTE]Originally posted by Zoran
[B]
Good job doing the math, but if you go back to my post you'll see that the
Reply
Old Jun 10, 2003 | 03:46 PM
  #183  
FCGuy's Avatar
Registered User
 
Joined: Nov 2001
Posts: 594
Likes: 0
From: Rochester
Default

Originally posted by Zoran
OK, my previous post finally made me realize what is absolutely the simplest way to explain why is it the HP that accelerates your car.

Wheel torque accelerates your car. Everyone (even the most stubborn "torque enthusiasts") will give you that.

Since WheelTorque = EngineTorque*Gearing, and Gearing = EngineRPM/WheelRPM, and EngineHP = EngineTorque * EngineRPM, we get that:

WheelTorque = EngineHP/WheelRPM

At any given speed, there's nothing you can do to change your wheel RPM, so your wheel torque (and thus your acceleration) is DIRECTLY proportional to the engine HP at that RPM.

I really cannot think of a simpler way to explain this.
Bravo! 100% correct, and I hope as clear.
Reply
Old Jun 10, 2003 | 04:47 PM
  #184  
Zoran's Avatar
Registered User
 
Joined: Apr 2001
Posts: 854
Likes: 0
From: Houston
Default

[QUOTE]Originally posted by wc_one
What I'm saying is at any given time the max rate of acceleration is at the max torque.
Reply
Old Jun 10, 2003 | 04:52 PM
  #185  
Destiny2002's Avatar
Thread Starter
Registered User
 
Joined: Feb 2002
Posts: 2,960
Likes: 2
From: Transporter
Default

Reply
Old Jun 10, 2003 | 04:54 PM
  #186  
wc_one's Avatar
Registered User
 
Joined: Jan 2002
Posts: 250
Likes: 0
From: Redford, MI
Default

[QUOTE]Originally posted by Zoran
[B]
What does this mean? "At any given time"?

In any given gear, maximum acceleration occurs at the torque peak.
Reply
Old Jun 10, 2003 | 05:07 PM
  #187  
Destiny2002's Avatar
Thread Starter
Registered User
 
Joined: Feb 2002
Posts: 2,960
Likes: 2
From: Transporter
Default

Reply
Old Jun 11, 2003 | 02:35 AM
  #188  
Destiny2002's Avatar
Thread Starter
Registered User
 
Joined: Feb 2002
Posts: 2,960
Likes: 2
From: Transporter
Default

Reply
Old Jun 11, 2003 | 03:09 AM
  #189  
FYRHWK1's Avatar
Registered User
 
Joined: Jul 2002
Posts: 163
Likes: 0
From: NY
Default

i've heard that as well, removing 1 lb of rotational weight is like removing 4-5 lbs of sprung mass, then you also have to take into account how much faster the car will be able to rev now that the rotational resistance has lowered and all that goes with that. the 2900 lbs would bebare curb with little gsa in it i'm sure, no driver nor rotational as you said, but that would get tricky adding up the rotational weight unless you know all of the driveshaft, flywheel and prezzurized wheel & tire weights, as well as anything else like halfshafts and so on.

I'd say it proves the same thing really, the actual numbers might be off bu the curves wouldn't change much, you'd still accelerate roughly with your torque curve.
Reply
Old Jun 11, 2003 | 06:42 AM
  #190  
Zoran's Avatar
Registered User
 
Joined: Apr 2001
Posts: 854
Likes: 0
From: Houston
Default

[QUOTE]Originally posted by wc_one
[B]

"At any given time" you can only be in one gear (you cannot be in two different gears at the same time) so "maximum acceleration occurs at the torque peak" which is what I mean and we're agreeing on.
Reply



All times are GMT -8. The time now is 12:12 AM.