Differences between old and updated oil bolts.
Joined: Oct 2000
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From: Lisbon
[QUOTE]Originally posted by gernby
[B]
If "a shade less than 2mm diameter" is about 1.9 mm, and "a shade over 1mm diameter" is about 1.1 mm, then the old bolts would have about 5.7 mm^2 and the new bolts would have about 3.8 mm^2.
[B]
If "a shade less than 2mm diameter" is about 1.9 mm, and "a shade over 1mm diameter" is about 1.1 mm, then the old bolts would have about 5.7 mm^2 and the new bolts would have about 3.8 mm^2.
Joined: Oct 2000
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From: Redmond, WA
Originally posted by Luis
If the problem was pressure drop and not flow, then 4 x 1.1mm diameter holes perform better than 2 x 1.9mm holes, as pressure drop is inversely proportional to hole diameter and not cross sectional area.
If the problem was pressure drop and not flow, then 4 x 1.1mm diameter holes perform better than 2 x 1.9mm holes, as pressure drop is inversely proportional to hole diameter and not cross sectional area.
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From: Lisbon
Originally posted by vapors2k
The bolt is referred to as banjo bolts b/c they are similar to the banjo bolts used in brake lines (connecting brake line to caliper)
The bolt is referred to as banjo bolts b/c they are similar to the banjo bolts used in brake lines (connecting brake line to caliper)
... and I thought they were called so, because they resemble banjo tuning pegs
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Joined: Mar 2002
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Originally posted by Luis
If the problem was pressure drop and not flow, then 4 x 1.1mm diameter holes perform better than 2 x 1.9mm holes, as pressure drop is inversely proportional to hole diameter and not cross sectional area.
If the problem was pressure drop and not flow, then 4 x 1.1mm diameter holes perform better than 2 x 1.9mm holes, as pressure drop is inversely proportional to hole diameter and not cross sectional area.
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From: Lisbon
I don't understand what's so confusing.
The pressure drop is *directly* proportional to the decrease in diameter.
Thus it is not directly proportional to the area. (If you want, it is proportional to the decrease of the square root of the area).
And thus, adding up areas to compare the efficiency of the new bolts, as gernby was doing, is not a good idea imho, if the issue is one of pressure drop.
The pressure drop is *directly* proportional to the decrease in diameter.
Thus it is not directly proportional to the area. (If you want, it is proportional to the decrease of the square root of the area).
And thus, adding up areas to compare the efficiency of the new bolts, as gernby was doing, is not a good idea imho, if the issue is one of pressure drop.
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Consider water pouring out of a hose. If you pinch the hose at the end, it will cause pressure to build up and the water will squirt with force. However, if you pinch the hose in the middle, it will just slow the flow of the water at the end. It seems to me that the new bolts will be like pinching the middle of the hose.